Solve {l}{4x-2y=1}{x=8}

$$\left. \begin{array} { l } { 4 x - 2 y = 1 } \\ { x = 8 } \end{array} \right.$$

Solve for x, y

$$x=8$$

$$y = \frac{31}{2} = 15\frac{1}{2} = 15.5$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$4\times 8-2y=1$$

Multiply 4 and 8 to get 32.

$$32-2y=1$$

Subtract 32 from both sides.

$$-2y=1-32$$

Subtract 32 from 1 to get -31.

$$-2y=-31$$

Divide both sides by -2.

$$y=\frac{-31}{-2}$$

Fraction \frac{-31}{-2} can be simplified to \frac{31}{2} by removing the negative sign from both the numerator and the denominator.

$$y=\frac{31}{2}$$

The system is now solved.

$$x=8 y=\frac{31}{2}$$