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8-4x=Y
Consider the second equation. Swap sides so that all variable terms are on the left hand side.
-4x=Y-8
Subtract 8 from both sides.
-4x=Y-8,4x+y=10
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
-4x=Y-8
Pick one of the two equations which is more simple to solve for x by isolating x on the left hand side of the equal sign.
x=-\frac{Y}{4}+2
Divide both sides by -4.
4\left(-\frac{Y}{4}+2\right)+y=10
Substitute -\frac{Y}{4}+2 for x in the other equation, 4x+y=10.
8-Y+y=10
Multiply 4 times -\frac{Y}{4}+2.
y=Y+2
Subtract 8-Y from both sides of the equation.
x=-\frac{Y}{4}+2,y=Y+2
The system is now solved.