Solve {l}{4x+8=300}{5y+x=200}

$$\left. \begin{array} { l } { 4 x + 8 = 300 } \\ { 5 y + x = 200 } \end{array} \right.$$

Solve for x, y

$$x=73$$

$$y = \frac{127}{5} = 25\frac{2}{5} = 25.4$$

Solution Steps

Consider the first equation. Subtract 8 from both sides.

$$4x=300-8$$

Subtract 8 from 300 to get 292.

$$4x=292$$

Divide both sides by 4.

$$x=\frac{292}{4}$$

Divide 292 by 4 to get 73.

$$x=73$$

Consider the second equation. Insert the known values of variables into the equation.

$$5y+73=200$$

Subtract 73 from both sides.

$$5y=200-73$$

Subtract 73 from 200 to get 127.

$$5y=127$$

Divide both sides by 5.

$$y=\frac{127}{5}$$

The system is now solved.

$$x=73 y=\frac{127}{5}$$