Solve {l}{4x+3x^2-5=y}{x=5}

$$\left. \begin{array} { l } { 4 x + 3 x ^ { 2 } - 5 = y } \\ { x = 5 } \end{array} \right.$$

Solve for x, y

$$x=5$$

$$y=90$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$4\times 5+3\times 5^{2}-5=y$$

Multiply 4 and 5 to get 20.

$$20+3\times 5^{2}-5=y$$

Calculate 5 to the power of 2 and get 25.

$$20+3\times 25-5=y$$

Multiply 3 and 25 to get 75.

$$20+75-5=y$$

Add 20 and 75 to get 95.

$$95-5=y$$

Subtract 5 from 95 to get 90.

$$90=y$$

Swap sides so that all variable terms are on the left hand side.

$$y=90$$

The system is now solved.

$$x=5 y=90$$