Solve {l}{4-2x=6}{text{Solvefor}ytext{where}}{y=-6x+3x-5}

$$\left. \begin{array} { l } { 4 - 2 x = 6 }\\ { \text{Solve for } y \text{ where} } \\ { y = -6 x + 3 x - 5 } \end{array} \right.$$

Solve for x, y

$$y=-2$$

Solution Steps

Consider the first equation. Subtract 4 from both sides.

$$-2x=6-4$$

Subtract 4 from 6 to get 2.

$$-2x=2$$

Divide both sides by -2.

$$x=\frac{2}{-2}$$

Divide 2 by -2 to get -1.

$$x=-1$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=-6\left(-1\right)+3\left(-1\right)-5$$

Do the multiplications.

$$y=6-3-5$$

Subtract 3 from 6 to get 3.

$$y=3-5$$

Subtract 5 from 3 to get -2.

$$y=-2$$

The system is now solved.

$$x=-1 y=-2$$