Solve {l}{44/5div3/5+5+4/5*3/10-frac{1}{5}}{24div3+5+frac{4}{5}*3-1}

$$\left. \begin{array} { l } { 4 \frac { 4 } { 5 } \div \frac { 3 } { 5 } + 5 + \frac { 4 } { 5 } \times \frac { 3 } { 10 } - \frac { 1 } { 5 } } \\ { 24 \div 3 + 5 + \frac { 4 } { 5 } \times 3 - 1 } \end{array} \right.$$

Sort

$$\frac{326}{25},\ \frac{72}{5}$$

Solution Steps

Divide \frac{4\times 5+4}{5} by \frac{3}{5} by multiplying \frac{4\times 5+4}{5} by the reciprocal of \frac{3}{5}.

$$sort(\frac{\left(4\times 5+4\right)\times 5}{5\times 3}+5+\frac{4}{5}\times \frac{3}{10}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Cancel out 5 in both numerator and denominator.

$$sort(\frac{4+4\times 5}{3}+5+\frac{4}{5}\times \frac{3}{10}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Multiply 4 and 5 to get 20.

$$sort(\frac{4+20}{3}+5+\frac{4}{5}\times \frac{3}{10}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Add 4 and 20 to get 24.

$$sort(\frac{24}{3}+5+\frac{4}{5}\times \frac{3}{10}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Divide 24 by 3 to get 8.

$$sort(8+5+\frac{4}{5}\times \frac{3}{10}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Add 8 and 5 to get 13.

$$sort(13+\frac{4}{5}\times \frac{3}{10}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Multiply \frac{4}{5} times \frac{3}{10} by multiplying numerator times numerator and denominator times denominator.

$$sort(13+\frac{4\times 3}{5\times 10}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Do the multiplications in the fraction \frac{4\times 3}{5\times 10}.

$$sort(13+\frac{12}{50}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Reduce the fraction \frac{12}{50} to lowest terms by extracting and canceling out 2.

$$sort(13+\frac{6}{25}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Convert 13 to fraction \frac{325}{25}.

$$sort(\frac{325}{25}+\frac{6}{25}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Since \frac{325}{25} and \frac{6}{25} have the same denominator, add them by adding their numerators.

$$sort(\frac{325+6}{25}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Add 325 and 6 to get 331.

$$sort(\frac{331}{25}-\frac{1}{5},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Least common multiple of 25 and 5 is 25. Convert \frac{331}{25} and \frac{1}{5} to fractions with denominator 25.

$$sort(\frac{331}{25}-\frac{5}{25},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Since \frac{331}{25} and \frac{5}{25} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{331-5}{25},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Subtract 5 from 331 to get 326.

$$sort(\frac{326}{25},\frac{24}{3}+5+\frac{4}{5}\times 3-1)$$

Divide 24 by 3 to get 8.

$$sort(\frac{326}{25},8+5+\frac{4}{5}\times 3-1)$$

Add 8 and 5 to get 13.

$$sort(\frac{326}{25},13+\frac{4}{5}\times 3-1)$$

Express \frac{4}{5}\times 3 as a single fraction.

$$sort(\frac{326}{25},13+\frac{4\times 3}{5}-1)$$

Multiply 4 and 3 to get 12.

$$sort(\frac{326}{25},13+\frac{12}{5}-1)$$

Convert 13 to fraction \frac{65}{5}.

$$sort(\frac{326}{25},\frac{65}{5}+\frac{12}{5}-1)$$

Since \frac{65}{5} and \frac{12}{5} have the same denominator, add them by adding their numerators.

$$sort(\frac{326}{25},\frac{65+12}{5}-1)$$

Add 65 and 12 to get 77.

$$sort(\frac{326}{25},\frac{77}{5}-1)$$

Convert 1 to fraction \frac{5}{5}.

$$sort(\frac{326}{25},\frac{77}{5}-\frac{5}{5})$$

Since \frac{77}{5} and \frac{5}{5} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{326}{25},\frac{77-5}{5})$$

Subtract 5 from 77 to get 72.

$$sort(\frac{326}{25},\frac{72}{5})$$

Least common denominator of the numbers in the list \frac{326}{25},\frac{72}{5} is 25. Convert numbers in the list to fractions with denominator 25.

$$\frac{326}{25},\frac{360}{25}$$

Evaluate

$$\frac{326}{25},\ \frac{72}{5}$$