Solve {l}{4+3}{18/4+2}

$$\left. \begin{array} { l } { 4 + 3 } \\ { \frac { 18 } { 4 } + 2 } \end{array} \right.$$

Sort

$$\frac{13}{2},7$$

Solution Steps

Add 4 and 3 to get 7.

$$sort(7,\frac{18}{4}+2)$$

Reduce the fraction \frac{18}{4} to lowest terms by extracting and canceling out 2.

$$sort(7,\frac{9}{2}+2)$$

Convert 2 to fraction \frac{4}{2}.

$$sort(7,\frac{9}{2}+\frac{4}{2})$$

Since \frac{9}{2} and \frac{4}{2} have the same denominator, add them by adding their numerators.

$$sort(7,\frac{9+4}{2})$$

Add 9 and 4 to get 13.

$$sort(7,\frac{13}{2})$$

Convert decimal numbers in the list 7,\frac{13}{2} to fractions.

$$7,\frac{13}{2}$$

To sort the list, start from a single element 7.

$$7$$

Insert \frac{13}{2} to the appropriate location in the new list.

$$\frac{13}{2},7$$

Evaluate

$$7,\ \frac{13}{2}$$