Solve {l}{382*10^-4}{0.12*10^-2}

$$\left. \begin{array} { l } { 382 \cdot 10 ^ { - 4 } } \\ { 0.12 \cdot 10 ^ { - 2 } } \end{array} \right.$$

Sort

$$0.0012,0.0382$$

Solution Steps

Calculate 10 to the power of -4 and get \frac{1}{10000}.

$$sort(382\times \frac{1}{10000},0.12\times 10^{-2})$$

Multiply 382 and \frac{1}{10000} to get \frac{191}{5000}.

$$sort(\frac{191}{5000},0.12\times 10^{-2})$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$sort(\frac{191}{5000},0.12\times \frac{1}{100})$$

Multiply 0.12 and \frac{1}{100} to get \frac{3}{2500}.

$$sort(\frac{191}{5000},\frac{3}{2500})$$

Least common denominator of the numbers in the list \frac{191}{5000},\frac{3}{2500} is 5000. Convert numbers in the list to fractions with denominator 5000.

$$\frac{191}{5000},\frac{6}{5000}$$

To sort the list, start from a single element \frac{191}{5000}.

$$\frac{191}{5000}$$

Insert \frac{6}{5000} to the appropriate location in the new list.

$$\frac{6}{5000},\frac{191}{5000}$$

Replace the obtained fractions with the initial values.

$$\frac{3}{2500},\frac{191}{5000}$$

Evaluate

$$0.0382,\ 0.0012$$