Solve for x_1, x
x=\frac{5}{7}\approx 0.714285714
x_{1}=37
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x_{1}=37
Consider the first equation. Swap sides so that all variable terms are on the left hand side.
x=\frac{30}{42}
Consider the second equation. Divide both sides by 42.
x=\frac{5}{7}
Reduce the fraction \frac{30}{42} to lowest terms by extracting and canceling out 6.
x_{1}=37 x=\frac{5}{7}
The system is now solved.
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