Solve for x, a, z
x=336
z=330
a=\frac{3}{5}=0.6
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x=336
Consider the first equation. Swap sides so that all variable terms are on the left hand side.
336=10a+330
Consider the second equation. Insert the known values of variables into the equation.
10a+330=336
Swap sides so that all variable terms are on the left hand side.
10a=336-330
Subtract 330 from both sides.
10a=6
Subtract 330 from 336 to get 6.
a=\frac{6}{10}
Divide both sides by 10.
a=\frac{3}{5}
Reduce the fraction \frac{6}{10} to lowest terms by extracting and canceling out 2.
x=336 a=\frac{3}{5} z=330
The system is now solved.
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