Solve {l}{3.4x=(x+4)-40}{x+y=80}

$$\left. \begin{array} { l } { 3.4 x = ( x + 4 ) - 40 } \\ { x + y = 80 } \end{array} \right.$$

Solve for x, y

$$x=-15$$

$$y=95$$

Solution Steps

Consider the first equation. Subtract 40 from 4 to get -36.

$$3.4x=x-36$$

Subtract x from both sides.

$$3.4x-x=-36$$

Combine 3.4x and -x to get 2.4x.

$$2.4x=-36$$

Divide both sides by 2.4.

$$x=\frac{-36}{2.4}$$

Expand \frac{-36}{2.4} by multiplying both numerator and the denominator by 10.

$$x=\frac{-360}{24}$$

Divide -360 by 24 to get -15.

$$x=-15$$

Consider the second equation. Insert the known values of variables into the equation.

$$-15+y=80$$

Add 15 to both sides.

$$y=80+15$$

Add 80 and 15 to get 95.

$$y=95$$

The system is now solved.

$$x=-15 y=95$$