Solve {l}{3y+9=0}{6x+y=0}

$$\left. \begin{array} { l } { 3 y + 9 = 0 } \\ { 6 x + y = 0 } \end{array} \right.$$

Solve for y, x

$$x=\frac{1}{2}=0.5$$

$$y=-3$$

Solution Steps

Consider the first equation. Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$3y=-9$$

Divide both sides by 3.

$$y=\frac{-9}{3}$$

Divide -9 by 3 to get -3.

$$y=-3$$

Consider the second equation. Insert the known values of variables into the equation.

$$6x-3=0$$

Add 3 to both sides. Anything plus zero gives itself.

$$6x=3$$

Divide both sides by 6.

$$x=\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$x=\frac{1}{2}$$

The system is now solved.

$$y=-3 x=\frac{1}{2}$$