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Solve for x, y, z
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y=3x+7
Solve 3x-y=-7 for y.
3x+7+4z=3
Substitute 3x+7 for y in the equation y+4z=3.
x=-\frac{4}{3}-\frac{4}{3}z z=x+\frac{5}{2}
Solve the second equation for x and the third equation for z.
z=-\frac{4}{3}-\frac{4}{3}z+\frac{5}{2}
Substitute -\frac{4}{3}-\frac{4}{3}z for x in the equation z=x+\frac{5}{2}.
z=\frac{1}{2}
Solve z=-\frac{4}{3}-\frac{4}{3}z+\frac{5}{2} for z.
x=-\frac{4}{3}-\frac{4}{3}\times \frac{1}{2}
Substitute \frac{1}{2} for z in the equation x=-\frac{4}{3}-\frac{4}{3}z.
x=-2
Calculate x from x=-\frac{4}{3}-\frac{4}{3}\times \frac{1}{2}.
y=3\left(-2\right)+7
Substitute -2 for x in the equation y=3x+7.
y=1
Calculate y from y=3\left(-2\right)+7.
x=-2 y=1 z=\frac{1}{2}
The system is now solved.