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Solve for x, y, z
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y=3x+z-4
Solve 3x-y+z=4 for y.
2x+3\left(3x+z-4\right)-z=12 x+3x+z-4+z=6
Substitute 3x+z-4 for y in the second and third equation.
x=\frac{24}{11}-\frac{2}{11}z z=5-2x
Solve these equations for x and z respectively.
z=5-2\left(\frac{24}{11}-\frac{2}{11}z\right)
Substitute \frac{24}{11}-\frac{2}{11}z for x in the equation z=5-2x.
z=1
Solve z=5-2\left(\frac{24}{11}-\frac{2}{11}z\right) for z.
x=\frac{24}{11}-\frac{2}{11}
Substitute 1 for z in the equation x=\frac{24}{11}-\frac{2}{11}z.
x=2
Calculate x from x=\frac{24}{11}-\frac{2}{11}.
y=3\times 2+1-4
Substitute 2 for x and 1 for z in the equation y=3x+z-4.
y=3
Calculate y from y=3\times 2+1-4.
x=2 y=3 z=1
The system is now solved.