Solve for x, y
x=16
y=-89
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3x=48
Consider the first equation. Add 47 and 1 to get 48.
x=\frac{48}{3}
Divide both sides by 3.
x=16
Divide 48 by 3 to get 16.
7\times 16+y=23
Consider the second equation. Insert the known values of variables into the equation.
112+y=23
Multiply 7 and 16 to get 112.
y=23-112
Subtract 112 from both sides.
y=-89
Subtract 112 from 23 to get -89.
x=16 y=-89
The system is now solved.
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