Solve for x
x=-\frac{y^{2}}{3}+3
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3x+y^{2}=9
Multiply y and y to get y^{2}.
3x=9-y^{2}
Subtract y^{2} from both sides.
\frac{3x}{3}=\frac{9-y^{2}}{3}
Divide both sides by 3.
x=\frac{9-y^{2}}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{y^{2}}{3}+3
Divide -y^{2}+9 by 3.
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