Solve {l}{3x+y=7}{2x+1=8}

$$\left. \begin{array} { l } { 3 x + y = 7 } \\ { 2 x + 1 = 8 } \end{array} \right.$$

Solve for x, y

$$x = \frac{7}{2} = 3\frac{1}{2} = 3.5$$

$$y = -\frac{7}{2} = -3\frac{1}{2} = -3.5$$

Solution Steps

Consider the second equation. Subtract 1 from both sides.

$$2x=8-1$$

Subtract 1 from 8 to get 7.

$$2x=7$$

Divide both sides by 2.

$$x=\frac{7}{2}$$

Consider the first equation. Insert the known values of variables into the equation.

$$3\times \frac{7}{2}+y=7$$

Multiply 3 and \frac{7}{2} to get \frac{21}{2}.

$$\frac{21}{2}+y=7$$

Subtract \frac{21}{2} from both sides.

$$y=7-\frac{21}{2}$$

Subtract \frac{21}{2} from 7 to get -\frac{7}{2}.

$$y=-\frac{7}{2}$$

The system is now solved.

$$x=\frac{7}{2} y=-\frac{7}{2}$$