Solve {l}{3x+4=8}{3xy+6=2}

$$\left. \begin{array} { l } { 3 x + 4 = 8 } \\ { 3 x y + 6 = 2 } \end{array} \right.$$

Solve for x, y

$$x = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333$$

$$y=-1$$

Solution Steps

Consider the first equation. Subtract 4 from both sides.

$$3x=8-4$$

Subtract 4 from 8 to get 4.

$$3x=4$$

Divide both sides by 3.

$$x=\frac{4}{3}$$

Consider the second equation. Insert the known values of variables into the equation.

$$3\times \frac{4}{3}y+6=2$$

Multiply 3 and \frac{4}{3} to get 4.

$$4y+6=2$$

Subtract 6 from both sides.

$$4y=2-6$$

Subtract 6 from 2 to get -4.

$$4y=-4$$

Divide both sides by 4.

$$y=\frac{-4}{4}$$

Divide -4 by 4 to get -1.

$$y=-1$$

The system is now solved.

$$x=\frac{4}{3} y=-1$$