Solve {l}{3-20c=9}{-2x=46}

$$\left. \begin{array} { l } { 3 - 20 c = 9 } \\ { - 2 x = 46 } \end{array} \right.$$

Solve for c, x

$$x=-23$$

$$c=-\frac{3}{10}=-0.3$$

Solution Steps

Consider the first equation. Subtract 3 from both sides.

$$-20c=9-3$$

Subtract 3 from 9 to get 6.

$$-20c=6$$

Divide both sides by -20.

$$c=\frac{6}{-20}$$

Reduce the fraction \frac{6}{-20} to lowest terms by extracting and canceling out 2.

$$c=-\frac{3}{10}$$

Consider the second equation. Divide both sides by -2.

$$x=\frac{46}{-2}$$

Divide 46 by -2 to get -23.

$$x=-23$$

The system is now solved.

$$c=-\frac{3}{10} x=-23$$