Solve {l}{33/5+6/25-3/5}{*10-9/10}

$$\left. \begin{array} { l } { 3 \frac { 3 } { 5 } + \frac { 6 } { 25 } - \frac { 3 } { 5 } } \\ { \times 10 - \frac { 9 } { 10 } } \end{array} \right.$$

Evaluate

$$-\frac{153}{50}=-3.06$$

Solution Steps

Multiply 3 and 5 to get 15.

$$\frac{15+3}{5}+\frac{6}{25}-\frac{3}{5}\times 10-\frac{9}{10}$$

Add 15 and 3 to get 18.

$$\frac{18}{5}+\frac{6}{25}-\frac{3}{5}\times 10-\frac{9}{10}$$

Least common multiple of 5 and 25 is 25. Convert \frac{18}{5} and \frac{6}{25} to fractions with denominator 25.

$$\frac{90}{25}+\frac{6}{25}-\frac{3}{5}\times 10-\frac{9}{10}$$

Since \frac{90}{25} and \frac{6}{25} have the same denominator, add them by adding their numerators.

$$\frac{90+6}{25}-\frac{3}{5}\times 10-\frac{9}{10}$$

Add 90 and 6 to get 96.

$$\frac{96}{25}-\frac{3}{5}\times 10-\frac{9}{10}$$

Express \frac{3}{5}\times 10 as a single fraction.

$$\frac{96}{25}-\frac{3\times 10}{5}-\frac{9}{10}$$

Multiply 3 and 10 to get 30.

$$\frac{96}{25}-\frac{30}{5}-\frac{9}{10}$$

Divide 30 by 5 to get 6.

$$\frac{96}{25}-6-\frac{9}{10}$$

Convert 6 to fraction \frac{150}{25}.

$$\frac{96}{25}-\frac{150}{25}-\frac{9}{10}$$

Since \frac{96}{25} and \frac{150}{25} have the same denominator, subtract them by subtracting their numerators.

$$\frac{96-150}{25}-\frac{9}{10}$$

Subtract 150 from 96 to get -54.

$$-\frac{54}{25}-\frac{9}{10}$$

Least common multiple of 25 and 10 is 50. Convert -\frac{54}{25} and \frac{9}{10} to fractions with denominator 50.

$$-\frac{108}{50}-\frac{45}{50}$$

Since -\frac{108}{50} and \frac{45}{50} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-108-45}{50}$$

Subtract 45 from -108 to get -153.

$$-\frac{153}{50}$$

Factor

$$-\frac{153}{50} = -3\frac{3}{50} = -3.06$$