Solve {l}{32/5+13/4div7/16}{2^2+(-1)*164}

$$\left. \begin{array} { l } { 3 \frac { 2 } { 5 } + 1 \frac { 3 } { 4 } \div \frac { 7 } { 16 } } \\ { 2 ^ { 2 } + ( - 1 ) \times 164 } \end{array} \right.$$

Sort

$$-160,\frac{37}{5}$$

Solution Steps

Multiply 3 and 5 to get 15.

$$sort(\frac{15+2}{5}+\frac{\frac{1\times 4+3}{4}}{\frac{7}{16}},2^{2}-164)$$

Add 15 and 2 to get 17.

$$sort(\frac{17}{5}+\frac{\frac{1\times 4+3}{4}}{\frac{7}{16}},2^{2}-164)$$

Divide \frac{1\times 4+3}{4} by \frac{7}{16} by multiplying \frac{1\times 4+3}{4} by the reciprocal of \frac{7}{16}.

$$sort(\frac{17}{5}+\frac{\left(1\times 4+3\right)\times 16}{4\times 7},2^{2}-164)$$

Cancel out 4 in both numerator and denominator.

$$sort(\frac{17}{5}+\frac{4\left(3+4\right)}{7},2^{2}-164)$$

Add 3 and 4 to get 7.

$$sort(\frac{17}{5}+\frac{4\times 7}{7},2^{2}-164)$$

Multiply 4 and 7 to get 28.

$$sort(\frac{17}{5}+\frac{28}{7},2^{2}-164)$$

Divide 28 by 7 to get 4.

$$sort(\frac{17}{5}+4,2^{2}-164)$$

Convert 4 to fraction \frac{20}{5}.

$$sort(\frac{17}{5}+\frac{20}{5},2^{2}-164)$$

Since \frac{17}{5} and \frac{20}{5} have the same denominator, add them by adding their numerators.

$$sort(\frac{17+20}{5},2^{2}-164)$$

Add 17 and 20 to get 37.

$$sort(\frac{37}{5},2^{2}-164)$$

Calculate 2 to the power of 2 and get 4.

$$sort(\frac{37}{5},4-164)$$

Subtract 164 from 4 to get -160.

$$sort(\frac{37}{5},-160)$$

Convert decimal numbers in the list \frac{37}{5},-160 to fractions.

$$\frac{37}{5},-160$$

To sort the list, start from a single element \frac{37}{5}.

$$\frac{37}{5}$$

Insert -160 to the appropriate location in the new list.

$$-160,\frac{37}{5}$$

Evaluate

$$\frac{37}{5},\ -160$$