Solve {l}{31/3+23/4}{144div6}

$$\left. \begin{array} { l } { 3 \frac { 1 } { 3 } + 2 \frac { 3 } { 4 } } \\ { 144 \div 6 } \end{array} \right.$$

Sort

$$\frac{73}{12},\ 24$$

Solution Steps

Multiply 3 and 3 to get 9.

$$sort(\frac{9+1}{3}+\frac{2\times 4+3}{4},\frac{144}{6})$$

Add 9 and 1 to get 10.

$$sort(\frac{10}{3}+\frac{2\times 4+3}{4},\frac{144}{6})$$

Multiply 2 and 4 to get 8.

$$sort(\frac{10}{3}+\frac{8+3}{4},\frac{144}{6})$$

Add 8 and 3 to get 11.

$$sort(\frac{10}{3}+\frac{11}{4},\frac{144}{6})$$

Least common multiple of 3 and 4 is 12. Convert \frac{10}{3} and \frac{11}{4} to fractions with denominator 12.

$$sort(\frac{40}{12}+\frac{33}{12},\frac{144}{6})$$

Since \frac{40}{12} and \frac{33}{12} have the same denominator, add them by adding their numerators.

$$sort(\frac{40+33}{12},\frac{144}{6})$$

Add 40 and 33 to get 73.

$$sort(\frac{73}{12},\frac{144}{6})$$

Divide 144 by 6 to get 24.

$$sort(\frac{73}{12},24)$$

Convert decimal numbers in the list \frac{73}{12},24 to fractions.

$$\frac{73}{12},24$$

Evaluate

$$\frac{73}{12},\ 24$$