Solve {l}{3*(-5)-(-2)*(-3+1)+8*(-3)}{-5+(6-4)*(-2)-(-8)*0+(-12)}

$$\left. \begin{array} { l } { 3 \cdot ( - 5 ) - ( - 2 ) \cdot ( - 3 + 1 ) + 8 \cdot ( - 3 ) } \\ { - 5 + ( 6 - 4 ) \cdot ( - 2 ) - ( - 8 ) \cdot 0 + ( - 12 ) } \end{array} \right.$$

Evaluate

$$-64$$

Solution Steps

Multiply 3 and -5 to get -15.

$$-15-\left(-2\left(-3+1\right)\right)+8\left(-3\right)-5+\left(6-4\right)\left(-2\right)-\left(-8\times 0\right)-12$$

Add -3 and 1 to get -2.

$$-15-\left(-2\left(-2\right)\right)+8\left(-3\right)-5+\left(6-4\right)\left(-2\right)-\left(-8\times 0\right)-12$$

Multiply -2 and -2 to get 4.

$$-15-4+8\left(-3\right)-5+\left(6-4\right)\left(-2\right)-\left(-8\times 0\right)-12$$

Subtract 4 from -15 to get -19.

$$-19+8\left(-3\right)-5+\left(6-4\right)\left(-2\right)-\left(-8\times 0\right)-12$$

Multiply 8 and -3 to get -24.

$$-19-24-5+\left(6-4\right)\left(-2\right)-\left(-8\times 0\right)-12$$

Subtract 24 from -19 to get -43.

$$-43-5+\left(6-4\right)\left(-2\right)-\left(-8\times 0\right)-12$$

Subtract 5 from -43 to get -48.

$$-48+\left(6-4\right)\left(-2\right)-\left(-8\times 0\right)-12$$

Subtract 4 from 6 to get 2.

$$-48+2\left(-2\right)-\left(-8\times 0\right)-12$$

Multiply 2 and -2 to get -4.

$$-48-4-\left(-8\times 0\right)-12$$

Subtract 4 from -48 to get -52.

$$-52-\left(-8\times 0\right)-12$$

Multiply -8 and 0 to get 0.

$$-52-0-12$$

Subtract 0 from -52 to get -52.

$$-52-12$$

Subtract 12 from -52 to get -64.

$$-64$$

Factor

$$-64$$