Solve {l}{3*(-2)+(-6):(-1)}{[3-(-5)]*(-6)-(-1)^3}

$$\left. \begin{array} { l } { 3 \cdot ( - 2 ) + ( - 6 ) : ( - 1 ) } \\ { [ 3 - ( - 5 ) ] \cdot ( - 6 ) - ( - 1 ) ^ { 3 } } \end{array} \right.$$

Sort

$$-47,0$$

Solution Steps

Multiply 3 and -2 to get -6.

$$sort(-6+\frac{-6}{-1},\left(3-\left(-5\right)\right)\left(-6\right)-\left(-1\right)^{3})$$

Fraction \frac{-6}{-1} can be simplified to 6 by removing the negative sign from both the numerator and the denominator.

$$sort(-6+6,\left(3-\left(-5\right)\right)\left(-6\right)-\left(-1\right)^{3})$$

Add -6 and 6 to get 0.

$$sort(0,\left(3-\left(-5\right)\right)\left(-6\right)-\left(-1\right)^{3})$$

The opposite of -5 is 5.

$$sort(0,\left(3+5\right)\left(-6\right)-\left(-1\right)^{3})$$

Add 3 and 5 to get 8.

$$sort(0,8\left(-6\right)-\left(-1\right)^{3})$$

Multiply 8 and -6 to get -48.

$$sort(0,-48-\left(-1\right)^{3})$$

Calculate -1 to the power of 3 and get -1.

$$sort(0,-48-\left(-1\right))$$

The opposite of -1 is 1.

$$sort(0,-48+1)$$

Add -48 and 1 to get -47.

$$sort(0,-47)$$

To sort the list, start from a single element 0.

$$0$$

Insert -47 to the appropriate location in the new list.

$$-47,0$$

Evaluate

$$0,\ -47$$