Solve {l}{3*(-11)+22:(-2)}{-4*[-7+(-3^2+6)*(-2)]}

$$\left. \begin{array} { l } { 3 \cdot ( - 11 ) + 22 : ( - 2 ) } \\ { - 4 \cdot [ - 7 + ( - 3 ^ { 2 } + 6 ) \cdot ( - 2 ) ] } \end{array} \right.$$

Evaluate

$$-40$$

Solution Steps

Multiply 3 and -11 to get -33.

$$-33+\frac{22}{-2}-4\left(-7+\left(-3^{2}+6\right)\left(-2\right)\right)$$

Divide 22 by -2 to get -11.

$$-33-11-4\left(-7+\left(-3^{2}+6\right)\left(-2\right)\right)$$

Subtract 11 from -33 to get -44.

$$-44-4\left(-7+\left(-3^{2}+6\right)\left(-2\right)\right)$$

Calculate 3 to the power of 2 and get 9.

$$-44-4\left(-7+\left(-9+6\right)\left(-2\right)\right)$$

Add -9 and 6 to get -3.

$$-44-4\left(-7-3\left(-2\right)\right)$$

Multiply -3 and -2 to get 6.

$$-44-4\left(-7+6\right)$$

Add -7 and 6 to get -1.

$$-44-4\left(-1\right)$$

Multiply 4 and -1 to get -4.

$$-44-\left(-4\right)$$

The opposite of -4 is 4.

$$-44+4$$

Add -44 and 4 to get -40.

$$-40$$

Factor

$$-40$$