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Solve for a, b, c
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-2=c 3=a+b+c -5=9a+3b+c
Reorder the equations.
c=-2
Solve -2=c for c.
3=a+b-2 -5=9a+3b-2
Substitute -2 for c in the second and third equation.
b=-a+5 a=-\frac{1}{3}-\frac{1}{3}b
Solve these equations for b and a respectively.
a=-\frac{1}{3}-\frac{1}{3}\left(-a+5\right)
Substitute -a+5 for b in the equation a=-\frac{1}{3}-\frac{1}{3}b.
a=-3
Solve a=-\frac{1}{3}-\frac{1}{3}\left(-a+5\right) for a.
b=-\left(-3\right)+5
Substitute -3 for a in the equation b=-a+5.
b=8
Calculate b from b=-\left(-3\right)+5.
a=-3 b=8 c=-2
The system is now solved.