Solve {l}{298}{*594}

$$\left. \begin{array} { l } { 298 } \\ { \times 594 } \end{array} \right.$$

Evaluate

$$177012$$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}298\\\underline{\times\phantom{999}594}\\\end{array}$$

Now multiply the first number with the 1^{st} digit in 2^{nd} number to get intermediate results. That is Multiply 298 with 4. Write the result 1192 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}298\\\underline{\times\phantom{999}594}\\\phantom{\times99}1192\\\end{array}$$

Now multiply the first number with the 2^{nd} digit in 2^{nd} number to get intermediate results. That is Multiply 298 with 9. Write the result 2682 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}298\\\underline{\times\phantom{999}594}\\\phantom{\times99}1192\\\phantom{\times9}2682\phantom{9}\\\end{array}$$

Now multiply the first number with the 3^{rd} digit in 2^{nd} number to get intermediate results. That is Multiply 298 with 5. Write the result 1490 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}298\\\underline{\times\phantom{999}594}\\\phantom{\times99}1192\\\phantom{\times9}2682\phantom{9}\\\underline{\phantom{\times}1490\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times999}298\\\underline{\times\phantom{999}594}\\\phantom{\times99}1192\\\phantom{\times9}2682\phantom{9}\\\underline{\phantom{\times}1490\phantom{99}}\\\phantom{\times}177012\end{array}$$

Factor

$$2^{2}\times 3^{3}\times 11\times 149$$