Solve {l}{282+718+796+524+804+376}{52+136+48+64}{135+248+322+65}

$$\left. \begin{array} { l } { 282 + 718 + 796 + 524 + 804 + 376 } \\ { 52 + 136 + 48 + 64 } \\ { 135 + 248 + 322 + 65 } \end{array} \right.$$

Sort

$$300,770,3500$$

Solution Steps

Add 282 and 718 to get 1000.

$$sort(1000+796+524+804+376,52+136+48+64,135+248+322+65)$$

Add 1000 and 796 to get 1796.

$$sort(1796+524+804+376,52+136+48+64,135+248+322+65)$$

Add 1796 and 524 to get 2320.

$$sort(2320+804+376,52+136+48+64,135+248+322+65)$$

Add 2320 and 804 to get 3124.

$$sort(3124+376,52+136+48+64,135+248+322+65)$$

Add 3124 and 376 to get 3500.

$$sort(3500,52+136+48+64,135+248+322+65)$$

Add 52 and 136 to get 188.

$$sort(3500,188+48+64,135+248+322+65)$$

Add 188 and 48 to get 236.

$$sort(3500,236+64,135+248+322+65)$$

Add 236 and 64 to get 300.

$$sort(3500,300,135+248+322+65)$$

Add 135 and 248 to get 383.

$$sort(3500,300,383+322+65)$$

Add 383 and 322 to get 705.

$$sort(3500,300,705+65)$$

Add 705 and 65 to get 770.

$$sort(3500,300,770)$$

To sort the list, start from a single element 3500.

$$3500$$

Insert 300 to the appropriate location in the new list.

$$300,3500$$

Insert 770 to the appropriate location in the new list.

$$300,770,3500$$

Evaluate

$$3500,\ 300,\ 770$$