Solve {l}{27-5/2-(1/4+5/8)-(7/8+frac{1}{1})}{8quad(7-2)+10}

$$\left. \begin{array} { l } { 27 - \frac { 5 } { 2 } - ( \frac { 1 } { 4 } + \frac { 5 } { 8 } ) - ( \frac { 7 } { 8 } + \frac { 1 } { 1 } ) } \\ { 8 \quad ( 7 - 2 ) + 10 } \end{array} \right.$$

Sort

$$\frac{87}{4},\ 50$$

Solution Steps

Divide 1 by 1 to get 1.

$$sort(27-\frac{5}{2}-\left(\frac{1}{4}+\frac{5}{8}\right)-\left(\frac{7}{8}+1\right),8\left(7-2\right)+10)$$

Convert 27 to fraction \frac{54}{2}.

$$sort(\frac{54}{2}-\frac{5}{2}-\left(\frac{1}{4}+\frac{5}{8}\right)-\left(\frac{7}{8}+1\right),8\left(7-2\right)+10)$$

Since \frac{54}{2} and \frac{5}{2} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{54-5}{2}-\left(\frac{1}{4}+\frac{5}{8}\right)-\left(\frac{7}{8}+1\right),8\left(7-2\right)+10)$$

Subtract 5 from 54 to get 49.

$$sort(\frac{49}{2}-\left(\frac{1}{4}+\frac{5}{8}\right)-\left(\frac{7}{8}+1\right),8\left(7-2\right)+10)$$

Least common multiple of 4 and 8 is 8. Convert \frac{1}{4} and \frac{5}{8} to fractions with denominator 8.

$$sort(\frac{49}{2}-\left(\frac{2}{8}+\frac{5}{8}\right)-\left(\frac{7}{8}+1\right),8\left(7-2\right)+10)$$

Since \frac{2}{8} and \frac{5}{8} have the same denominator, add them by adding their numerators.

$$sort(\frac{49}{2}-\frac{2+5}{8}-\left(\frac{7}{8}+1\right),8\left(7-2\right)+10)$$

Add 2 and 5 to get 7.

$$sort(\frac{49}{2}-\frac{7}{8}-\left(\frac{7}{8}+1\right),8\left(7-2\right)+10)$$

Least common multiple of 2 and 8 is 8. Convert \frac{49}{2} and \frac{7}{8} to fractions with denominator 8.

$$sort(\frac{196}{8}-\frac{7}{8}-\left(\frac{7}{8}+1\right),8\left(7-2\right)+10)$$

Since \frac{196}{8} and \frac{7}{8} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{196-7}{8}-\left(\frac{7}{8}+1\right),8\left(7-2\right)+10)$$

Subtract 7 from 196 to get 189.

$$sort(\frac{189}{8}-\left(\frac{7}{8}+1\right),8\left(7-2\right)+10)$$

Convert 1 to fraction \frac{8}{8}.

$$sort(\frac{189}{8}-\left(\frac{7}{8}+\frac{8}{8}\right),8\left(7-2\right)+10)$$

Since \frac{7}{8} and \frac{8}{8} have the same denominator, add them by adding their numerators.

$$sort(\frac{189}{8}-\frac{7+8}{8},8\left(7-2\right)+10)$$

Add 7 and 8 to get 15.

$$sort(\frac{189}{8}-\frac{15}{8},8\left(7-2\right)+10)$$

Since \frac{189}{8} and \frac{15}{8} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{189-15}{8},8\left(7-2\right)+10)$$

Subtract 15 from 189 to get 174.

$$sort(\frac{174}{8},8\left(7-2\right)+10)$$

Reduce the fraction \frac{174}{8} to lowest terms by extracting and canceling out 2.

$$sort(\frac{87}{4},8\left(7-2\right)+10)$$

Subtract 2 from 7 to get 5.

$$sort(\frac{87}{4},8\times 5+10)$$

Multiply 8 and 5 to get 40.

$$sort(\frac{87}{4},40+10)$$

Add 40 and 10 to get 50.

$$sort(\frac{87}{4},50)$$

Convert decimal numbers in the list \frac{87}{4},50 to fractions.

$$\frac{87}{4},50$$

Evaluate

$$\frac{87}{4},\ 50$$