Solve {l}{25x+05y=480}{x+y=68}

$$\left. \begin{array} { l } { 25 x + 05 y = 480 } \\ { x + y = 68 } \end{array} \right.$$

Solve for x, y

$$x = \frac{96}{5} = 19\frac{1}{5} = 19.2$$

$$y = \frac{244}{5} = 48\frac{4}{5} = 48.8$$

Solution Steps

Consider the first equation. Multiply 0 and 5 to get 0.

$$25x+0y=480$$

Anything times zero gives zero.

$$25x+0=480$$

Anything plus zero gives itself.

$$25x=480$$

Divide both sides by 25.

$$x=\frac{480}{25}$$

Reduce the fraction \frac{480}{25} to lowest terms by extracting and canceling out 5.

$$x=\frac{96}{5}$$

Consider the second equation. Insert the known values of variables into the equation.

$$\frac{96}{5}+y=68$$

Subtract \frac{96}{5} from both sides.

$$y=68-\frac{96}{5}$$

Subtract \frac{96}{5} from 68 to get \frac{244}{5}.

$$y=\frac{244}{5}$$

The system is now solved.

$$x=\frac{96}{5} y=\frac{244}{5}$$