Solve {l}{25:5+7*7-9+205-3*12}{35:7+5*44-27+46+33}

$$\left. \begin{array} { l } { 25 : 5 + 7 \cdot 7 - 9 + 205 - 3 \cdot 12 } \\ { 35 : 7 + 5 \cdot 44 - 27 + 46 + 33 } \end{array} \right.$$

Sort

$$214,\ 277$$

Solution Steps

Divide 25 by 5 to get 5.

$$sort(5+7\times 7-9+205-3\times 12,\frac{35}{7}+5\times 44-27+46+33)$$

Multiply 7 and 7 to get 49.

$$sort(5+49-9+205-3\times 12,\frac{35}{7}+5\times 44-27+46+33)$$

Add 5 and 49 to get 54.

$$sort(54-9+205-3\times 12,\frac{35}{7}+5\times 44-27+46+33)$$

Subtract 9 from 54 to get 45.

$$sort(45+205-3\times 12,\frac{35}{7}+5\times 44-27+46+33)$$

Add 45 and 205 to get 250.

$$sort(250-3\times 12,\frac{35}{7}+5\times 44-27+46+33)$$

Multiply 3 and 12 to get 36.

$$sort(250-36,\frac{35}{7}+5\times 44-27+46+33)$$

Subtract 36 from 250 to get 214.

$$sort(214,\frac{35}{7}+5\times 44-27+46+33)$$

Divide 35 by 7 to get 5.

$$sort(214,5+5\times 44-27+46+33)$$

Multiply 5 and 44 to get 220.

$$sort(214,5+220-27+46+33)$$

Add 5 and 220 to get 225.

$$sort(214,225-27+46+33)$$

Subtract 27 from 225 to get 198.

$$sort(214,198+46+33)$$

Add 198 and 46 to get 244.

$$sort(214,244+33)$$

Add 244 and 33 to get 277.

$$sort(214,277)$$

The list values are already in order.

$$214,277$$

Evaluate

$$214,\ 277$$