Solve {l}{216div272+2}{324div2div2div2}

$$\left. \begin{array} { l } { 216 \div 272 + 2 } \\ { 324 \div 2 \div 2 \div 2 } \end{array} \right.$$

Sort

$$\frac{95}{34},\ \frac{81}{2}$$

Solution Steps

Reduce the fraction \frac{216}{272} to lowest terms by extracting and canceling out 8.

$$sort(\frac{27}{34}+2,\frac{\frac{\frac{324}{2}}{2}}{2})$$

Convert 2 to fraction \frac{68}{34}.

$$sort(\frac{27}{34}+\frac{68}{34},\frac{\frac{\frac{324}{2}}{2}}{2})$$

Since \frac{27}{34} and \frac{68}{34} have the same denominator, add them by adding their numerators.

$$sort(\frac{27+68}{34},\frac{\frac{\frac{324}{2}}{2}}{2})$$

Add 27 and 68 to get 95.

$$sort(\frac{95}{34},\frac{\frac{\frac{324}{2}}{2}}{2})$$

Express \frac{\frac{\frac{324}{2}}{2}}{2} as a single fraction.

$$sort(\frac{95}{34},\frac{\frac{324}{2}}{2\times 2})$$

Divide 324 by 2 to get 162.

$$sort(\frac{95}{34},\frac{162}{2\times 2})$$

Multiply 2 and 2 to get 4.

$$sort(\frac{95}{34},\frac{162}{4})$$

Reduce the fraction \frac{162}{4} to lowest terms by extracting and canceling out 2.

$$sort(\frac{95}{34},\frac{81}{2})$$

Least common denominator of the numbers in the list \frac{95}{34},\frac{81}{2} is 34. Convert numbers in the list to fractions with denominator 34.

$$\frac{95}{34},\frac{1377}{34}$$

Evaluate

$$\frac{95}{34},\ \frac{81}{2}$$