Solve {l}{21-13+8+1+8-23}{15*3-4-1+5*8-1}

$$\left. \begin{array} { l } { 21 - 13 + 8 + 1 + 8 - 23 } \\ { 15 \cdot 3 - 4 - 1 + 5 \cdot 8 - 1 } \end{array} \right.$$

Sort

$$2,\ 79$$

Solution Steps

Subtract 13 from 21 to get 8.

$$sort(8+8+1+8-23,15\times 3-4-1+5\times 8-1)$$

Add 8 and 8 to get 16.

$$sort(16+1+8-23,15\times 3-4-1+5\times 8-1)$$

Add 16 and 1 to get 17.

$$sort(17+8-23,15\times 3-4-1+5\times 8-1)$$

Add 17 and 8 to get 25.

$$sort(25-23,15\times 3-4-1+5\times 8-1)$$

Subtract 23 from 25 to get 2.

$$sort(2,15\times 3-4-1+5\times 8-1)$$

Multiply 15 and 3 to get 45. Multiply 5 and 8 to get 40.

$$sort(2,45-4-1+40-1)$$

Subtract 4 from 45 to get 41.

$$sort(2,41-1+40-1)$$

Subtract 1 from 41 to get 40.

$$sort(2,40+40-1)$$

Add 40 and 40 to get 80.

$$sort(2,80-1)$$

Subtract 1 from 80 to get 79.

$$sort(2,79)$$

The list values are already in order.

$$2,79$$

Evaluate

$$2,\ 79$$