Solve {l}{200+25m=c}{250+20m=6}

$$\left. \begin{array} { l } { 200 + 25 m = c } \\ { 250 + 20 m = 6 } \end{array} \right.$$

Solve for m, c

$$m = -\frac{61}{5} = -12\frac{1}{5} = -12.2$$

$$c=-105$$

Solution Steps

Consider the second equation. Subtract 250 from both sides.

$$20m=6-250$$

Subtract 250 from 6 to get -244.

$$20m=-244$$

Divide both sides by 20.

$$m=\frac{-244}{20}$$

Reduce the fraction \frac{-244}{20} to lowest terms by extracting and canceling out 4.

$$m=-\frac{61}{5}$$

Consider the first equation. Insert the known values of variables into the equation.

$$200+25\left(-\frac{61}{5}\right)=c$$

Multiply 25 and -\frac{61}{5} to get -305.

$$200-305=c$$

Subtract 305 from 200 to get -105.

$$-105=c$$

Swap sides so that all variable terms are on the left hand side.

$$c=-105$$

The system is now solved.

$$m=-\frac{61}{5} c=-105$$