Solve {l}{20c+3y=11}{2x-4y=-24}

$$\left. \begin{array} { l } { 20 c + 3 y = 11 } \\ { 2 x - 4 y = - 24 } \end{array} \right.$$

Solve for x, y

$$x=\frac{-40c-14}{3}$$

$$y=\frac{11-20c}{3}$$

Steps Using Substitution

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$$3y+20c=11,-4y+2x=-24$$

Pick one of the two equations which is more simple to solve for y by isolating y on the left hand side of the equal sign.

$$3y+20c=11$$

Subtract 20c from both sides of the equation.

$$3y=11-20c$$

Divide both sides by 3.

$$y=\frac{11-20c}{3}$$

Substitute \frac{11-20c}{3} for y in the other equation, -4y+2x=-24.

$$-4\times \frac{11-20c}{3}+2x=-24$$

Multiply -4 times \frac{11-20c}{3}.

$$\frac{80c-44}{3}+2x=-24$$

Subtract \frac{-44+80c}{3} from both sides of the equation.

$$2x=\frac{-80c-28}{3}$$

Divide both sides by 2.

$$x=\frac{-40c-14}{3}$$

The system is now solved.

$$y=\frac{11-20c}{3},x=\frac{-40c-14}{3}$$