Solve {l}{20a^3-1a}{m(3m+6)-3(m^2+4m+1)}

$$\left. \begin{array} { l } { 20 a ^ { 3 } - 1 a } \\ { m ( 3 m + 6 ) - 3 ( m ^ { 2 } + 4 m + 1 ) } \end{array} \right.$$

Least Common Multiple

$$3a\left(2m+1\right)\left(20a^{2}-1\right)$$

Solution Steps

Factor the expressions that are not already factored.

$$20a^{3}-a=a\left(20a^{2}-1\right) -3-6m=3\left(-2m-1\right)$$

Identify all the factors and their highest power in all expressions. Multiply the highest powers of these factors to get the least common multiple.

$$3a\left(2m+1\right)\left(20a^{2}-1\right)$$

Expand the expression.

$$120ma^{3}-6am+60a^{3}-3a$$

Evaluate

$$20a^{3}-a,\ -6m-3$$