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Solve for z, x
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2z=11-5
Consider the first equation. Subtract 5 from both sides.
2z=6
Subtract 5 from 11 to get 6.
z=\frac{6}{2}
Divide both sides by 2.
z=3
Divide 6 by 2 to get 3.
\frac{3}{x}-5=3
Consider the second equation. Insert the known values of variables into the equation.
3+x\left(-5\right)=3x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
3+x\left(-5\right)-3x=0
Subtract 3x from both sides.
3-8x=0
Combine x\left(-5\right) and -3x to get -8x.
-8x=-3
Subtract 3 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-3}{-8}
Divide both sides by -8.
x=\frac{3}{8}
Fraction \frac{-3}{-8} can be simplified to \frac{3}{8} by removing the negative sign from both the numerator and the denominator.
z=3 x=\frac{3}{8}
The system is now solved.