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-3x=2
Consider the second equation. Combine 4x and -7x to get -3x.
x=-\frac{2}{3}
Divide both sides by -3.
2\left(-\frac{2}{3}\right)-y=3
Consider the first equation. Insert the known values of variables into the equation.
-\frac{4}{3}-y=3
Multiply 2 and -\frac{2}{3} to get -\frac{4}{3}.
-y=3+\frac{4}{3}
Add \frac{4}{3} to both sides.
-y=\frac{13}{3}
Add 3 and \frac{4}{3} to get \frac{13}{3}.
y=\frac{\frac{13}{3}}{-1}
Divide both sides by -1.
y=\frac{13}{3\left(-1\right)}
Express \frac{\frac{13}{3}}{-1} as a single fraction.
y=\frac{13}{-3}
Multiply 3 and -1 to get -3.
y=-\frac{13}{3}
Fraction \frac{13}{-3} can be rewritten as -\frac{13}{3} by extracting the negative sign.
x=-\frac{2}{3} y=-\frac{13}{3}
The system is now solved.