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Solve for x, y
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x=\frac{2}{3}
Consider the second equation. Divide both sides by 3.
2\times \frac{2}{3}-y=1
Consider the first equation. Insert the known values of variables into the equation.
\frac{4}{3}-y=1
Multiply 2 and \frac{2}{3} to get \frac{4}{3}.
-y=1-\frac{4}{3}
Subtract \frac{4}{3} from both sides.
-y=-\frac{1}{3}
Subtract \frac{4}{3} from 1 to get -\frac{1}{3}.
y=\frac{-\frac{1}{3}}{-1}
Divide both sides by -1.
y=\frac{-1}{3\left(-1\right)}
Express \frac{-\frac{1}{3}}{-1} as a single fraction.
y=\frac{1}{3}
Cancel out -1 in both numerator and denominator.
x=\frac{2}{3} y=\frac{1}{3}
The system is now solved.