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Solve for x, y
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3x=2
Consider the second equation. Combine x and 2x to get 3x.
x=\frac{2}{3}
Divide both sides by 3.
2\times \frac{2}{3}-3y=6
Consider the first equation. Insert the known values of variables into the equation.
\frac{4}{3}-3y=6
Multiply 2 and \frac{2}{3} to get \frac{4}{3}.
-3y=6-\frac{4}{3}
Subtract \frac{4}{3} from both sides.
-3y=\frac{14}{3}
Subtract \frac{4}{3} from 6 to get \frac{14}{3}.
y=\frac{\frac{14}{3}}{-3}
Divide both sides by -3.
y=\frac{14}{3\left(-3\right)}
Express \frac{\frac{14}{3}}{-3} as a single fraction.
y=\frac{14}{-9}
Multiply 3 and -3 to get -9.
y=-\frac{14}{9}
Fraction \frac{14}{-9} can be rewritten as -\frac{14}{9} by extracting the negative sign.
x=\frac{2}{3} y=-\frac{14}{9}
The system is now solved.