Solve for x, y
y=15
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2x-3+4x=0
Consider the first equation. Add 4x to both sides.
6x-3=0
Combine 2x and 4x to get 6x.
6x=3
Add 3 to both sides. Anything plus zero gives itself.
x=\frac{3}{6}
Divide both sides by 6.
x=\frac{1}{2}
Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.
x=\frac{1}{2} y=15
The system is now solved.
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