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Solve for x, y
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3x=1-2
Consider the second equation. Subtract 2 from both sides.
3x=-1
Subtract 2 from 1 to get -1.
x=-\frac{1}{3}
Divide both sides by 3.
2\left(-\frac{1}{3}\right)+y=0
Consider the first equation. Insert the known values of variables into the equation.
-\frac{2}{3}+y=0
Multiply 2 and -\frac{1}{3} to get -\frac{2}{3}.
y=\frac{2}{3}
Add \frac{2}{3} to both sides. Anything plus zero gives itself.
x=-\frac{1}{3} y=\frac{2}{3}
The system is now solved.