Solve for x, y
x = -\frac{20}{3} = -6\frac{2}{3} \approx -6.666666667
y = \frac{28}{27} = 1\frac{1}{27} \approx 1.037037037
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3x=-7-13
Consider the second equation. Subtract 13 from both sides.
3x=-20
Subtract 13 from -7 to get -20.
x=-\frac{20}{3}
Divide both sides by 3.
2\left(-\frac{20}{3}\right)+9y=-4
Consider the first equation. Insert the known values of variables into the equation.
-\frac{40}{3}+9y=-4
Multiply 2 and -\frac{20}{3} to get -\frac{40}{3}.
9y=-4+\frac{40}{3}
Add \frac{40}{3} to both sides.
9y=\frac{28}{3}
Add -4 and \frac{40}{3} to get \frac{28}{3}.
y=\frac{\frac{28}{3}}{9}
Divide both sides by 9.
y=\frac{28}{3\times 9}
Express \frac{\frac{28}{3}}{9} as a single fraction.
y=\frac{28}{27}
Multiply 3 and 9 to get 27.
x=-\frac{20}{3} y=\frac{28}{27}
The system is now solved.
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