Solve {l}{2x+9x=-2}{8x-6y=0}

$$\left. \begin{array} { l } { 2 x + 9 x = - 2 } \\ { 8 x - 6 y = 0 } \end{array} \right.$$

Solve for x, y

$$x=-\frac{2}{11}\approx -0.181818182$$

$$y=-\frac{8}{33}\approx -0.242424242$$

Solution Steps

Consider the first equation. Combine 2x and 9x to get 11x.

$$11x=-2$$

Divide both sides by 11.

$$x=-\frac{2}{11}$$

Consider the second equation. Insert the known values of variables into the equation.

$$8\left(-\frac{2}{11}\right)-6y=0$$

Multiply 8 and -\frac{2}{11} to get -\frac{16}{11}.

$$-\frac{16}{11}-6y=0$$

Add \frac{16}{11} to both sides. Anything plus zero gives itself.

$$-6y=\frac{16}{11}$$

Divide both sides by -6.

$$y=\frac{\frac{16}{11}}{-6}$$

Express \frac{\frac{16}{11}}{-6} as a single fraction.

$$y=\frac{16}{11\left(-6\right)}$$

Multiply 11 and -6 to get -66.

$$y=\frac{16}{-66}$$

Reduce the fraction \frac{16}{-66} to lowest terms by extracting and canceling out 2.

$$y=-\frac{8}{33}$$

The system is now solved.

$$x=-\frac{2}{11} y=-\frac{8}{33}$$