Solve {l}{2x+5=32}{z+x=16}

$$\left. \begin{array} { l } { 2 x + 5 = 32 } \\ { z + x = 16 } \end{array} \right.$$

Solve for x, z

$$x = \frac{27}{2} = 13\frac{1}{2} = 13.5$$

$$z = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

Solution Steps

Consider the first equation. Subtract 5 from both sides.

$$2x=32-5$$

Subtract 5 from 32 to get 27.

$$2x=27$$

Divide both sides by 2.

$$x=\frac{27}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$z+\frac{27}{2}=16$$

Subtract \frac{27}{2} from both sides.

$$z=16-\frac{27}{2}$$

Subtract \frac{27}{2} from 16 to get \frac{5}{2}.

$$z=\frac{5}{2}$$

The system is now solved.

$$x=\frac{27}{2} z=\frac{5}{2}$$