Solve {l}{2x+4x=40}{132-y=40}

$$\left. \begin{array} { l } { 2 x + 4 x = 40 } \\ { 132 - y = 40 } \end{array} \right.$$

Solve for x, y

$$x = \frac{20}{3} = 6\frac{2}{3} \approx 6.666666667$$

$$y=92$$

Solution Steps

Consider the first equation. Combine 2x and 4x to get 6x.

$$6x=40$$

Divide both sides by 6.

$$x=\frac{40}{6}$$

Reduce the fraction \frac{40}{6} to lowest terms by extracting and canceling out 2.

$$x=\frac{20}{3}$$

Consider the second equation. Subtract 132 from both sides.

$$-y=40-132$$

Subtract 132 from 40 to get -92.

$$-y=-92$$

Divide both sides by -1.

$$y=\frac{-92}{-1}$$

Fraction \frac{-92}{-1} can be simplified to 92 by removing the negative sign from both the numerator and the denominator.

$$y=92$$

The system is now solved.

$$x=\frac{20}{3} y=92$$