Solve for x, y
x=\frac{6-y_{2}}{7}
y=\frac{2y_{2}+23}{21}
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7x=6-y_{2},2x+3y=5
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
7x=6-y_{2}
Pick one of the two equations which is more simple to solve for x by isolating x on the left hand side of the equal sign.
x=\frac{6-y_{2}}{7}
Divide both sides by 7.
2\times \frac{6-y_{2}}{7}+3y=5
Substitute \frac{6-y_{2}}{7} for x in the other equation, 2x+3y=5.
\frac{12-2y_{2}}{7}+3y=5
Multiply 2 times \frac{6-y_{2}}{7}.
3y=\frac{2y_{2}+23}{7}
Subtract \frac{12-2y_{2}}{7} from both sides of the equation.
y=\frac{2y_{2}+23}{21}
Divide both sides by 3.
x=\frac{6-y_{2}}{7},y=\frac{2y_{2}+23}{21}
The system is now solved.
Examples
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Matrix
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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