Solve {l}{2x+1=13}{3y+4x=4}

$$\left. \begin{array} { l } { 2 x + 1 = 13 } \\ { 3 y + 4 x = 4 } \end{array} \right.$$

Solve for x, y

$$x=6$$

$$y = -\frac{20}{3} = -6\frac{2}{3} \approx -6.666666667$$

Solution Steps

Consider the first equation. Subtract 1 from both sides.

$$2x=13-1$$

Subtract 1 from 13 to get 12.

$$2x=12$$

Divide both sides by 2.

$$x=\frac{12}{2}$$

Divide 12 by 2 to get 6.

$$x=6$$

Consider the second equation. Insert the known values of variables into the equation.

$$3y+4\times 6=4$$

Multiply 4 and 6 to get 24.

$$3y+24=4$$

Subtract 24 from both sides.

$$3y=4-24$$

Subtract 24 from 4 to get -20.

$$3y=-20$$

Divide both sides by 3.

$$y=-\frac{20}{3}$$

The system is now solved.

$$x=6 y=-\frac{20}{3}$$