Solve {l}{2m-5=0}{2m-5n+20=0}

$$\left. \begin{array} { l } { 2 m - 5 = 0 } \\ { 2 m - 5 n + 20 = 0 } \end{array} \right.$$

Solve for m, n

$$m = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

$$n=5$$

Solution Steps

Consider the first equation. Add 5 to both sides. Anything plus zero gives itself.

$$2m=5$$

Divide both sides by 2.

$$m=\frac{5}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$2\times \frac{5}{2}-5n+20=0$$

Multiply 2 and \frac{5}{2} to get 5.

$$5-5n+20=0$$

Add 5 and 20 to get 25.

$$25-5n=0$$

Subtract 25 from both sides. Anything subtracted from zero gives its negation.

$$-5n=-25$$

Divide both sides by -5.

$$n=\frac{-25}{-5}$$

Divide -25 by -5 to get 5.

$$n=5$$

The system is now solved.

$$m=\frac{5}{2} n=5$$