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Solve for b, y
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2b+7-8b=-3
Consider the first equation. Subtract 8b from both sides.
-6b+7=-3
Combine 2b and -8b to get -6b.
-6b=-3-7
Subtract 7 from both sides.
-6b=-10
Subtract 7 from -3 to get -10.
b=\frac{-10}{-6}
Divide both sides by -6.
b=\frac{5}{3}
Reduce the fraction \frac{-10}{-6} to lowest terms by extracting and canceling out -2.
8y-9-5y=6
Consider the second equation. Subtract 5y from both sides.
3y-9=6
Combine 8y and -5y to get 3y.
3y=6+9
Add 9 to both sides.
3y=15
Add 6 and 9 to get 15.
y=\frac{15}{3}
Divide both sides by 3.
y=5
Divide 15 by 3 to get 5.
b=\frac{5}{3} y=5
The system is now solved.